What is the output of the following C++ program?

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---

#include<iostream>
using namespace std;
  
int x = 10;
void fun()
{
    int x = 2;
    {
        int x = 1;
        cout << ::x << endl; 
    }
}
  
int main()
{
    fun();
    return 0;
}

Output:
10

The global variable is referred to if the Scope Resolution Operator is put in front of a variable name. Therefore, the programme above will not compile if the following line is removed.