What is the output of the following C program?

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#include<stdio.h>
int main()
{
    int a[2][3] = {2,1,3,2,3,4};
    printf("Using pointer notations:\n");
    printf("%d %d %d\n", *(*(a+0)+0), *(*(a+0)+1), *(*(a+0)+2));
    printf("Using mixed notations:\n");
    printf("%d %d %d\n", *(a[1]+0), *(a[1]+1), *(a[1]+2));
    return 0;
}